Question

Sebuah taman berbentuk persegi panjang dengan ukuran panjang adalah (3x-2)meter dan lebar (2x+1) meter .jika keliling taman 38 meter ,hitunglah luas taman tersebut
MOHON bantuannnya
makassihhh

Answer 1

Diket :
p = (3x - 2) m
l = (2x - 1) m
K = 38 m

Ditanya :
L = ... ?

Jawab :
38 m = ( (3x - 2) + (2x - 1) ) x 2
38 m = (6x - 3x - 2x + 2) x 2
38 m = (x + 2) x 2
38 m = 2x + 4
38 m - 4 = 2x
34 = 2x
x = 34/2
x = 17

p = (3x - 2)
p = 3 x 17 - 2
p = 49 m

l = (2x - 1)
l = 2 x 17 - 1
l = 33 m

L = p x l
L = 49 m x 33 m
L = 1.617 m²

Answer 2

Diketahui: p = 3x-2  l = 2x+1

Keliling = 2p + 2l
= 2(3x-2) + 2(2x+1)
= 6x-4 + 4x+2
= 6x+4x-4+2
=10x-2
38 = 10x-2
38+2 = 10x
40 = 10x
4 = x

panjang = 3x-2
= 3(4) -2
= 12 - 2
= 10 m
lebar = 2x+1
= 2(4) +1
= 8 + 1
= 9 m

Luas = p.l
= 10.9
= 90 m2