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r = 2/a
deret geometrinya mempunyai rasio positif
a dan U3 ditanya
S3 = a(r^n - 1) / r - 1
7 = a(r^3 - 1) / r - 1
7 = a((2/a)^3 - 1) / (2/a) - 1
7 = a((8/a^3) - 1) / (2 - a)/a
7 = a((8 - a^3/a^3)) / (2 - a)/a
7 = (8 - a^3)/a^2 / (2 - a)/a
7 = (8 - a^3) / a(2 - a)
7 = (8 - a^3) / 2a - a^2
8 - a^3 = 7(2a - a^2)
8 - a^3 = 14a - 7a^2
a = 1 meter = tali terpendek
r = 2/a = 2/1 = 2
U3 = ar² = 1.(2)² = 1.4 = 4 meter = tali terpanjang