sebuah tabung mempunyai volume 55.440 cm³ jika tinggi tabung tersebut adalah 40 cm. berpakaian jari jari tabung tersebut
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V = πr²t
55.440 = 3,14 × r² × 40
r = √(55.440 ÷ 3,14 × 40)
r = √(55.440 ÷ 125,6)
r = √441,4 (dibulatkan)
r = √441
r = 21 cm
V = πR²T
55.440 = (3,14(R²(40)
55.440 = (3,14(40(R²)
55.440 = (125,6(R²)
125,6R² = 55.440
R² = 55.440/125,6
R² = 441,4
R² = 441
R = √441
R = √21²
R = 21 CM