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ditanyak : hipotenusa
jawab : (I) L.segitiga = 1/2 . a. t
6√10 = 1/2 . 6√2 . t
6 √10 = 3√2 . t ⇔ t = 6√10 : 3√2 = 2√5
(II) rumus hipotenusa = a² + t²
= (2√5)² + (6√2)² ⇔ 4√25 + 36√4 = (4.5) + (36.2)
= 20 + 72 = 92