Penjelasan dengan langkah-langkah:
1). teorema Phytagoras
[tex] {bc}^{2} = {ab}^{2} + {ac}^{2} \\ {bc}^{2} = {5}^{2} + {5}^{2} \\ {bc}^{2} = 25 + 25 \\ bc = \sqrt{25 + 25 } \\ bc = \sqrt{50} \\ bc = \sqrt{25 \times 2 } \\ bc = 5 \sqrt{2} [/tex]
2).teorema phytagoras
bc²= ab²+ac²
bc² = 7²+7²
bc² = 49 + 49
bc²= 98
bc =√98
bc = √49×2
bc= 7√2
1) BC = √5² + 5²
= √(5(5) + (5(5)
= √25 + 25
= √50
= √25.2
= √5².2
= 5√2 CM
2) BC = √7² + 7²
= √(7(7) + (7(7)
= √49 + 49
= √98
= √49.2
= √7².2
= 7√2 CM
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Penjelasan dengan langkah-langkah:
1). teorema Phytagoras
[tex] {bc}^{2} = {ab}^{2} + {ac}^{2} \\ {bc}^{2} = {5}^{2} + {5}^{2} \\ {bc}^{2} = 25 + 25 \\ bc = \sqrt{25 + 25 } \\ bc = \sqrt{50} \\ bc = \sqrt{25 \times 2 } \\ bc = 5 \sqrt{2} [/tex]
2).teorema phytagoras
bc²= ab²+ac²
bc² = 7²+7²
bc² = 49 + 49
bc²= 98
bc =√98
bc = √49×2
bc= 7√2
Verified answer
1) BC = √5² + 5²
= √(5(5) + (5(5)
= √25 + 25
= √50
= √25.2
= √5².2
= 5√2 CM
2) BC = √7² + 7²
= √(7(7) + (7(7)
= √49 + 49
= √98
= √49.2
= √7².2
= 7√2 CM