Question

Sebuah rangkaian listrik disusun secara paralel R1=4 R2=2 r=0,6 E=2

berapakah kuat arusnya

Answer 1

1/Rtot= 1/4 +1/2
1/R tot = 1/4+2/4
1/Rtot = 3/4
Rtot = 4/3

E = I (R+r)
2 = I (4/3 + 0)
2 = I x 4/3
I = 2 : 4/3
I = 1,5 A

Answer 2

1/Rtot= 1/4 +1/2
1/R tot = 1/4+2/4
1/Rtot = 3/4
Rtot = 4/3

E = I (R+r)
2 = I (4/3 + 0)
2 = I x 4/3
I = 2 : 4/3
I = 1,5 A