Tekanan air raksa = tekanan alkohol.P1=P2ρ1gh1=ρ2gh213,6x10³.18,84=ρ2.20ρ2 = (13,6x10³.18,84)/20ρ2 = 12,811.10³ kg/m3
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Tekanan air raksa = tekanan alkohol.
P1=P2
ρ1gh1=ρ2gh2
13,6x10³.18,84=ρ2.20
ρ2 = (13,6x10³.18,84)/20
ρ2 = 12,811.10³ kg/m3