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L0 = 1 m = 100 cm
T0 = 25 C
T = 50 C
dit : L ?
dijwb:
α tembaga = 0,000017/C
L = L0 (1 + α x ΔT)
= 100 (1 + 0,000017 x (50-25))
= 100 (1 + 0,000017 x 25)
= 100 (1 + 0,000425)
= 100,0425 cm (B)