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l₀ = 1 meter
t₁ = 25°C
t₂ = 175°C
Δt = t₂-t₁
Δt = 150
Dit = lt
Jwb =
lt = l₀.(1+α.Δt)
lt = 1.(1+1,7×10⁻⁵.150)
lt = 1(1+2,55×10⁻³
lt = 1+ 2,55×10⁻³
lt = 1,00255 m