Materi : Kesebangunan dan Kekonggruenan , Bangun Ruang Sisi Lengkung
Gambar yang Terlampirkan
a¹ = ( x + 35 ) , b¹ = 9
a² = x , b² = 5
________________/
a¹/a² = b¹/b²
( x + 35 )/x = 9/5
5( x + 35 ) = 9x
5x + 175 = 9x
9x - 5x = 175
4x = 175
x = 175/4 cm = 43,75 cm
x + 35 = 78,75
V = ⅓πr²t - ⅓πr²t
V = ⅓.π.9².78,75 - ⅓.π.5².43,75
V = ⅓.π.81.78,75 - ⅓.π.25.43,75
V = ⅓.π × 6.378,75 cm³ - ⅓.π × 1.093,75 cm³
V = ⅓.π × 5.285 cm³
V = ⅓ × 22 × 755 cm³
V = ⅓ × 16.610 cm³
V = 5.536⅔ cm³
Semoga bisa membantu
[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
x/(x + 35) = 9/5
5(x + 35) = 9(x)
5(x) + 5(35) = 9x
9x = 5x + 175
(9 - 5)x = 175
x = 175/4
x = 43,75 + 35
x = 78,75
MAKA :
V = 1/3(π(81(78,75) - 1/3(π(25(43,75)
= 1/3(π(6.378,75) - 1/3(π(1.093,75)
= 1/3(22/7(6.378,75 - 1.093,75)
= 1/3(22/7(5.285)
= 1/3(22(5.285/7)
= 1/3(22(755)
= 1/3(16.610)
= 16.610/3
= 5.536,667 CM³
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Verified answer
Materi : Kesebangunan dan Kekonggruenan , Bangun Ruang Sisi Lengkung
Gambar yang Terlampirkan
Tinggi Kerucut yang terpotong
a¹ = ( x + 35 ) , b¹ = 9
a² = x , b² = 5
________________/
a¹/a² = b¹/b²
( x + 35 )/x = 9/5
5( x + 35 ) = 9x
5x + 175 = 9x
9x - 5x = 175
4x = 175
x = 175/4 cm = 43,75 cm
x + 35 = 78,75
Langsung Saja
V = ⅓πr²t - ⅓πr²t
V = ⅓.π.9².78,75 - ⅓.π.5².43,75
V = ⅓.π.81.78,75 - ⅓.π.25.43,75
V = ⅓.π × 6.378,75 cm³ - ⅓.π × 1.093,75 cm³
V = ⅓.π × 5.285 cm³
V = ⅓ × 22 × 755 cm³
V = ⅓ × 16.610 cm³
V = 5.536⅔ cm³
Semoga bisa membantu
[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
x/(x + 35) = 9/5
5(x + 35) = 9(x)
5(x) + 5(35) = 9x
5x + 175 = 9x
9x = 5x + 175
(9 - 5)x = 175
4x = 175
x = 175/4
x = 43,75 + 35
x = 78,75
MAKA :
V = 1/3(π(81(78,75) - 1/3(π(25(43,75)
= 1/3(π(6.378,75) - 1/3(π(1.093,75)
= 1/3(22/7(6.378,75 - 1.093,75)
= 1/3(22/7(5.285)
= 1/3(22(5.285/7)
= 1/3(22(755)
= 1/3(16.610)
= 16.610/3
= 5.536,667 CM³