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Verified answer
ENERGI dan DAYA LISTRIKP = 500 MW = 500×10⁶ W
V = 1000 kV = 10⁶ V
i = __?
P = V i
500×10⁶ = 10⁶ • i
i = 500 A ✔️
arus yang mengalir pada kawat transmisi sebesar 500 A
Verified answer
Jawabannya:Mapel. : Fisika
Bab. : Energi dan Daya Listrik
Sub Bab : Daya Listrik
Pembahasan:
P = 500 MW
P = 500 × 10^6 W
Jadi :
P = V. i
500×10^6 = 10^6. i
i = 500×10^6 / 10^6
i = 500 Ampere → Jwbnya
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