Sebuah pelurubermassa 20 g ditembakkan dengan energi kinetik 2500 J. Kelajuan peluru tersebut adalah...
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2500=1/2 . 0,02 . v^2
2500=0,01 . v^2
v^2=250000
v=500 m/s
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m = 20 gram ⇒ 0,02 kg
Ek = 2500 J
Asked
v..?
Answer
Ek = 1/2 mv²
2500 = 1/2 . 0,02 . v²
2500 = 0.01v²
v² = 2500/0.01
v² = 250000
v = √250000
v = 500 m/s