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= (9 + 3) i + 9j
= 12i + 9j
r2 = ( + 3)i + 3(5) j
= (25 + 3)i + 15j
= 28i + 15j
perubahan posisi = r2 - r1
=28i + 15j - (12i + 9j)
= (16i + 6j)
besar =
= √216 . 36 = 96 satuan
arah = tanα =
=