Luas permukaan kerucut = π.r (r + s)
s = √r2 + t2
= √10^2 + 24^2
√100+576
√676
=26
=22/7 X 10(10+26)
=1130,4
kayknya slh soal tu karna jwbnnya ga bulat
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Luas permukaan kerucut = π.r (r + s)
s = √r2 + t2
= √10^2 + 24^2
√100+576
√676
=26
Luas permukaan kerucut = π.r (r + s)
=22/7 X 10(10+26)
=1130,4
kayknya slh soal tu karna jwbnnya ga bulat