Sebuah limas segi empat beraturan tingginya 12 cm, panjang rusuk tegaknya 15cm. volume limas ......cm3
musdali
Setengah sisi dari alas = sisi alas = 2 x 9 = 18
jadi volume limas = luas alas x t x1/3 = () x 12 x 1/3 = 324 x 12 x 1/3 = 3888/3 = 1296
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whongaliem
(1/2 x diagonal alas) = √{(sisi tgak)² - t² } = √ (15² - 12²) = √(225 - 144) = √81 = 9 diagonal alas = 18 s√2 = 18 ....kuadratkan 2 .s² = 324 s² =162 V limas = 1/3 x La x t = 1/3 x s² x t = 1/3 x 162 x 12 = 162 x 4 = 648 cm³
sisi alas = 2 x 9 = 18
jadi volume limas = luas alas x t x1/3
= () x 12 x 1/3
= 324 x 12 x 1/3
= 3888/3 = 1296
= √ (15² - 12²)
= √(225 - 144)
= √81
= 9
diagonal alas = 18
s√2 = 18 ....kuadratkan
2 .s² = 324
s² =162
V limas = 1/3 x La x t
= 1/3 x s² x t
= 1/3 x 162 x 12
= 162 x 4
= 648 cm³