Question

Sebuah limas alasnya berbentuk belah ketupat dengan panjang diagonal 36 cm dan 48cm,tinggi limas 25cm .hitunglah luas permukaan dan volume limas tersebut

Answer 1

Volume = 1/3 x 1/2 x d1 x d2 x t
1/3 ( 1/2 x 36 x 48 ) 25
1/3 ( 864 ) 25
7200cm³
------------------------
Luas permukaan
Alas = 864cm²
---------
x1 = √25²-√18²
x1 = 7 cm
2 ( 1/2 x 7 x 36 ) = 252cm²
-------
x2 = √25²-√24²
x2 = 1 cm
2 ( 1/2 x 1 x 48 ) = 48cm²
-----Total Luas permukaan = 864 + 252 + 48 = 1164cm²

Answer 2

 Volume = 1/3 x 1/2 x d1 x d2 x t
                1/3 ( 1/2 x 36 x 48 ) 25
                1/3 ( 864 ) 25
                7200cm³
========================================================
Luas permukaan
Alas = 864cm²
=============
x1 = √25²-√18²
x1 = 7 cm
2 ( 1/2 x 7 x 36 ) = 252cm²
-------
x2 = √25²-√24²
x2 = 1 cm
2 ( 1/2 x 1 x 48 ) = 48cm²
====Total Luas permukaan = 864 + 252 + 48 = 1164cm²====