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P = -100/PR (jika satuan cm)
P = kekuatan lensa
PR = fokus maximum
Diketahui = PR = 25 cm
Ditanya = P
Jawab=
P=-100/PR
P= -100/25
P = -4/1
P = -4
Jadi, kekuatan lensa jika jarak fokusnya 25 adalah 4. Karena cekung maka -4.