luas segitiga = ½ × a × t
= ½ × 6 × t
#1 cari dulu t dengan rumus pytagoras
t² = s² - ½alas²
t² = 5² - 3²
t² = 25 - 9
t² = 16
t = √16 = 4
= ½ × 6 × 4
= ½ × 24
= 12 cm²
maaf kalau salah
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luas segitiga = ½ × a × t
= ½ × 6 × t
#1 cari dulu t dengan rumus pytagoras
t² = s² - ½alas²
t² = 5² - 3²
t² = 25 - 9
t² = 16
t = √16 = 4
luas segitiga = ½ × a × t
= ½ × 6 × 4
= ½ × 24
= 12 cm²
maaf kalau salah