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10450 = Cx 55
C = 190
t₁ = 25°C
t₂ = 80°C
Δt = 80 - 25 = 55°C
Dit : kapasitas kalor (C) = ....?
Jwb : Q = C.Δt
C = Q/Δt
= 10450/55
= 190 J/⁰C