Jawaban:
volume kerucut tersebut adalah 1.155 cm³
V = ⅓πr²t
= ⅓ × 22/7 × 10,5² × 10
= 22/21 × 110,25 × 10
= 22 × 1.102,5/21
= 24.255/21
= 1.155 cm³
V = 1/3πR²T
= 1/3(22/7(10,5(10,5(10)
= 1/3(22/7(10,5(105)
= 1/3(22/7(1.102,5)
= 1/3(24.255/7)
= 1/3(3.465)
= 3.465/3
= 1.155 CM³
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Verified answer
Jawaban:
volume kerucut tersebut adalah 1.155 cm³
Penyelesaian:
V = ⅓πr²t
= ⅓ × 22/7 × 10,5² × 10
= 22/21 × 110,25 × 10
= 22 × 1.102,5/21
= 24.255/21
= 1.155 cm³
V = 1/3πR²T
= 1/3(22/7(10,5(10,5(10)
= 1/3(22/7(10,5(105)
= 1/3(22/7(1.102,5)
= 1/3(24.255/7)
= 1/3(3.465)
= 3.465/3
= 1.155 CM³