sebuah kerucut memiliki diameter 49 dan tinggi 12 Berapa Luas Permukaan kerucut tersebut?
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Materi : Bangun Ruang Sisi Lengkung
Luas Permukaan Kerucut
Lp = πr² + πrs
Lp = 22/7 . 7/2 . 7/2 + 22/7 . 49/2 . 27,28
Lp = 22 . ½ . 7/2 + 22 . 7/2 . ~ 27,3
Lp = 22 . ( 7/4 + 95 + 11/20 )
Lp = 22( 96 + 15/20 + 11/20 )
Lp = 22( 97,3 cm² )
Lp = 2.140,6 cm²
Semoga bisa membantu
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