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=√13²+16²
=√169+256
s=√425=20,6cm
a. l. permukaan kerucut=Πr(s+r)
=3,14×13(20,6+13)
=40,82×33,6
=1371,552cm²
b. v. kerucut=⅓Πr²t
=⅓×22/7×13²×16
=2832,7cm³