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Diket :Gaya tegangan kawat, F = 80 N
Pertambahan panjang kawat, ΔL = 5 mm = 5.10^-3 m
Luas penampang kawat, A = 2 mm^2 = 2.10^-6 m^2
Tanya :
A. Tegangan, σ = __?
B. Regangan, e = __?
C. Modulus, E = __?
Jawab :
Step 1
———-
Tegangan, σ = __?
σ = F/A
σ = 80/2.10^-6
σ = 40 x 10^6
σ = 4 x 10^7 N/m^2
Step 2
————
Regangan, e = __?
e = ΔL/L
e = 5.10^-3/L
Mohon maaf soal ini belum lengkap data panjang kawat semula ...
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