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Verified answer
Kurva awal y = mx + ckurva bayangan 3x - 2y + 12 = 0
matriks
tentukan titik kurva awal
substitusi x' dan y' ke persamaan bayangan
3x - 2y + 12 = 0
3x' - 2y' + 12 = 0
3 (2x + 5y) - 2(x + 4y) + 12 = 0
6x + 15y - 2x - 8y + 12 = 0
4x + 7y + 12 = 0
atau
y = (-4x - 12) / 7
sehingga persamaan garis lurusnya adalah