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n(S) = 6
Mata dadu kelipatan 2 adalah 2, 4, 6 berarti n(A) = 3
Banyak pelemparan N = 400
Ditanya
Frekuensi harapan munculnya mata dadu kelipatan 2
Penyelesaian
Peluang munculnya mata dadu kelipatan 2 adalah P(A) = n(A) / n(S)
P(A) = 3/6 = 1/2
Frekuensi harapan
FH = N x P(A)
∴ FH = 400 x 1/2 = 200
P(A) = 3/6 = 1/2
Frekuensi harapan
FH = N x P(A)
FH = 400 x 1/2 = 200
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