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Materi : Kinematika Gerak LurusSub bab : Gerak Vertikal
Diketahui :
y(t) = (30 +20t -10t²) meter
Ditanya :
ymaks = ?
Penyelesaian :
*Cari nilai maksimum (y' = 0)
y' = 0
20 - 20t = 0
20 = 20t
t = 1
Maka, ketinggian maksimum ada pada saat t = 1
*Cari ketinggian maksimum
y(1) = 30 + 20(1) - 10(1)² m
y(1) = 30+20-10 m
y(1) = 40 m
Jadi, ketinggian maksimum yg dapat dicapai bola adalah 40 meter
Jawaban : C
semoga membantu
-vin