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1/15 + 1/s' = 1/10
1/s' = 1/10 - 1/15
......= (3 - 2) / 30
......= 1/ 30
s' = 30 cm
karna Benda terletak di ruang 2. bayangan terletak di ruang 3
jadi sifat bayangan dinyatakan :
- nyata
- terbalik
- diperbesar
semoga membantu