Question

Sebuah benda terletak 60 cm didepan cermin cekung yang memiliki jari-jari 30 cm. Pembesaran bayangan yang terjadi adalah...

Answer 1

F = 30cm ÷ 2 = 15cm || 1/Si = 1/f - 1/So || 1/Si = 1/15 - 1/60 || 1/Si = (4-1)/60 || 1/Si = 3/60 || Si = 60/3 = 20cm || M = Si/So || M = 20cm/60cm = 1/3

Answer 2

F= R/2 = 30/2 = 15 1/si = 1/f - 1/so = 1/15 - 1/60 = 4-1/60 = 3/60 Si = 60/3 = 20cm M = si/so = 20/60 = 0,33 atau 1/3