Question

sebuah benda terletak 6 cm di depan cermin yg jarak fokusnya 4cm​

Answer 1

Penjelasan:

1/s' = 1/f - 1/s

1/s' = 1/4 - 1/6

1/s' = 6/24 - 4/24

1/s' = 2/24

s' = 24/2

s' = 12 cm

Answer 2

12 cm

Penjelasan:

Diketahui:

• f = 4 cm
• s = 6 cm

Ditanya:

• Jarak bayangan (s') = ... ?

Jawab:

• 1/s' = 1/f - 1/s
• 1/s' = 1/4 - 1/6
• 1/s' = (1 × 6) - (1 × 4) / (4 × 6)
• 1/s' = (6 - 4) / 24
• 1/s' = 2/24
• s' = 24/2
• s' = 12 cm

Kesimpulan:

Jadi, jarak bayangan nya adalah 12 cm