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°R = 4/5 x 20 = 4 x 4
= 16°R
°F = 9/5 x 20 + 32
= 9 x 4 + 32
= 36 + 32
= 68 °F
Tk = 293 K
Dit:
a. Suhu Reamur (tR)
b . Suhu Fahrenheit (tF)
Jawab:
utk memudahkan, cari dulu suhu celcius (tC)
tC = Tk - 273
tC = 293 - 273
tC = 20'C
maka:
a. tR = 4/5 x tC
tR = 4/5 x 20
tR = 16'R
b. tF = 9/5 x Tc + 32
tF = 9/5 x 20 + 32
tF = 36 + 32
tF = 68"F