Question

Sebuah benda setinggi 1 cm berada di depan lensa cekung dengan fokus 2 cm. jika jarak benda 4 cm. jika jarak benda 4 cm makan tentukan, (a) jarak bayangan (b) perbesaran (c) tinggi bayangan

Answer 1

1/S₁ = 1/f - 1/S₀
1/S₁ = 1/-2 - 1/4
1/S₁ = 2 - (-1)/-4
1/S₁ = 3/-4
1/S₁ = -0.75 cm

M = |S₁/S₀|
M = |0,75/4|
M = 0.1875 kali

M = |h₁/h₀|
0.1875 = |h₁/1|
h₁ = 0.1875 x 1
h₁ = 0.1875 cm