Question

Sebuah benda memiliki persamaan posisi.
r= (8t-4)i + (-3t kuadrat + 6t)j.
Hitunglah besarnya perpindahan dari t=1 sekon sampai t=1,5sekon

Answer 1

Verified answer

X(1 s) = (8(1) - 4)i+ (-3(1)² + 6(1)j
= 4i + 3j
|x(1s)| = √16+9 = 5 m

x(1,5) = (8*1,5 -4)i + (-3(1,5)² + 6(1,5))j
= 8i + (-6,75+ 9)j
= 8i + 2,25j
|x| = 18 m

x1 + x2 = xtotal = 23 m