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f = 15 cm
so = 20 cm
ditanya =
sifat sifat bayangan = ...
dijawab =
1 / f = 1 / so + 1 / si
1 / si = 1 / f - 1 / so
= 1 / 15 - 1 / 20
= 4 / 60 - 3 / 60
1 / si = 1 / 60
si = 60 cm
M = -si / so
= -60 cm / 20 cm
= -3
M = 3 kali secara terbalik
sifat bayangan =
1. nyata
2. terbalik
3. diperbesar