Sebuah benda diletakkan 30 cm di depan cermin cekung yang jarak fokusnya 10 cm .Tentukan pembesaran bayangannya !
RonaldRobi
1/s1 = 1/f - 1/so = 1/10 - 1/30 = 3-1/30 = 2/30 = 30/2 = 15 cm M = s1/so = 15/30 = 1/2 x
Semoga membantu, jadikan terbaik ya!
1 votes Thanks 2
fikriyah34
Diket : So = 30 cm f = 10 cm Ditanya : M ? Jawab : M = Si So 1= 1 + 1 f So Si 1 = 1 + 1 10 30 Si 1 = 1 - 1 Si 10 30 = 3 - 1 30 1 = 2 Si 30 Si = 30 2 Si = 15 cm M = Si So = 15 30 = 1 2 ket : M = perbesaran bayangan f = jarak fokus cermin So = jarak benda ke cermin Si = jarak bayangan ke cermin
thanks , semoga membantu ............ :D
2 votes Thanks 2
vikamonic12
MAKASIH MAKASH MAKASIH ATAS PENJELASANNYA LENGKAP DAN JELAS :D
= 1/10 - 1/30
= 3-1/30
= 2/30
= 30/2 = 15 cm
M = s1/so
= 15/30
= 1/2 x
Semoga membantu, jadikan terbaik ya!
f = 10 cm
Ditanya : M ?
Jawab : M = Si
So
1 = 1 + 1
f So Si
1 = 1 + 1
10 30 Si
1 = 1 - 1
Si 10 30
= 3 - 1
30
1 = 2
Si 30
Si = 30
2
Si = 15 cm
M = Si
So
= 15
30
= 1
2
ket : M = perbesaran bayangan
f = jarak fokus cermin
So = jarak benda ke cermin
Si = jarak bayangan ke cermin
thanks , semoga membantu ............ :D