Question

Sebuah benda di letakan 18 cm di ddepan cermin cekung jika jarak fokus cermin 6 cm hitunglah:
A.jarak bayangan
B.perbesaran bayangan

Answer 1

A. 1/6 - 1/18   = 1/s'
    3/18 - 1/18 = 1/s'
    s'              = 9 cm
b. M = s'/s
       = 9/18
        = 1/2 kali

Answer 2

Dik : 
s = 18 cm
f = 6 cm

dit 
s' ( jarak bayangan ) =.....
M ( perbesaran ) =.....

Jawab.....

1/f = 1/s' + 1/s
1/6 = 1/s' + 1/18
1/s' = 1/6 - 1/18
⇔
1/s' = 3/18 -1/18
1/s' = 2/18
1/s' = 1/9

s' = 9 cm



M = I s'/s I
M = I 9/18 I
M = 9/18
M = 1/2 kali

sip gan.........