Jawaban:
40 m/s
Penjelasan:
diketahui:
massa benda, m = 0.5 kg
ketinggian benda, h = 100 m
kecepatan awal, [tex] v_0 = 0 [/tex]
ditanya:
kecepatan benda di h = 20 m
penyelesaian:
Gunakan hukum kekekalan energi mekanik
[tex] \frac{1}{2} m v_{0}^{2} + mg h_{0} = \frac{1}{2} m v_{1}^{2} + mg h_{1} \\ 0 + gh_{0} = \frac{1}{2} {v_{1}}^{2} + gh_{1} \\ \frac{1}{2} {v_{1}}^{2} = g(h_{0} - h_{1}) \\ {v_{1}}^{2} = 2g(h_{0} - h_{1}) \\ v_{1} = \sqrt{2g(h_{0} - h_{1})} \\ = \sqrt{2 \times 10 \times (100 - 20)} \\ = \sqrt{200 \times 80} \\ = \sqrt{1600} \\ = 40[/tex]
Jadi, kecepatan benda di ketinggian 20 meter adalah 40 m/s
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Jawaban:
40 m/s
Penjelasan:
diketahui:
massa benda, m = 0.5 kg
ketinggian benda, h = 100 m
kecepatan awal, [tex] v_0 = 0 [/tex]
ditanya:
kecepatan benda di h = 20 m
penyelesaian:
Gunakan hukum kekekalan energi mekanik
[tex] \frac{1}{2} m v_{0}^{2} + mg h_{0} = \frac{1}{2} m v_{1}^{2} + mg h_{1} \\ 0 + gh_{0} = \frac{1}{2} {v_{1}}^{2} + gh_{1} \\ \frac{1}{2} {v_{1}}^{2} = g(h_{0} - h_{1}) \\ {v_{1}}^{2} = 2g(h_{0} - h_{1}) \\ v_{1} = \sqrt{2g(h_{0} - h_{1})} \\ = \sqrt{2 \times 10 \times (100 - 20)} \\ = \sqrt{200 \times 80} \\ = \sqrt{1600} \\ = 40[/tex]
Jadi, kecepatan benda di ketinggian 20 meter adalah 40 m/s