Question

Sebuah benda berjarak 10 cm di depan lensa cekung memiliki fokus 15 cm. Berapakah perbesaran bayangan yang dihasilkan??

Answer 1

1/si = 1/f - 1/ so
1/si = -1/15 - 1/10
1/si = -2/30 -3/30
1/si = -5/30
si = -6

M = si/ so = 6/10 = 0,6

Answer 2

1/s' = -1/f - 1/s
1/s' = -1/15 - 1/10
1/s' = -2-3/30
1/s' = -5/30
1/s' = -1/6
s' = -6

M = s'/s = 6/0 = 0,6x