sebuah belah ketupat memiliki panjang diagonal masing = 8cm dan 10 cm hitunglah Luasnya
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jwb
s^2 + s^2 = d^2 (pitagoras)
2s^2 = 8^2 + 10^2
2s^2 = 164
s^2 = 82
= √82
luas = d1 x d2 : 2
= 8 x 10 : 2
= 40
luas belah ketupat = 40 cm^2
Jawaban:
40 cm².
Penjelasan dengan langkah-langkah:
L = 1/2 x d1 x d2
L = 1/2 x 8 x 10
L = 40 cm²