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l=4x
t=3x
diagonal ruang=√p²+l²+t²
√200=√(5x)²+(4x)²+(3x)²
√200=√25x²+16x²+9x²
√200=√50x²
x²=200/50
x²=4
x=√4=2
panjang=5x=5. 2=10 cm
lebar=4x=4. 2=8 cm
tinggi=3x=3. 2=6 cm
luas sisi balok=2(p.l+p.t+l.t)
=2{(10.8)+(10.6)+(8.6)}
=2(80+60+48)
=2.188
=376cm²