SEBUAH BALOK MEMILIKI PANJANG 6CM , LEBAR 8CM , DAN TINGGI 10CM . TENTUKAN LUAS JARING JARING BALOK TERSEBUT
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LJB :
= 2(PL + PT + LT)
= 2(6(8) + (6(10) + (8(10)
= 2(48 + 60 + 80)
= 2(108 + 80)
= 2(188)
= 376 CM²
~~ DETAIL JAWABAN ~~
KELAS = 8
MATA PELAJARAN = MATEMATIKA
MATERI = BANGUN RUANG BALOK
KATA KUNCI = LUAS JARING-JARING BALOK
KODE SOAL = 2
KODE KATEGORISASI = 8.2.8