Question

sebuah balok dengan panjang 20 cm lebar 8 cm dan tinggi 5 cm luas jaring-jaring balok adalah​

Answer 1

jwb

luas jaring" balok = 2 x (p x l) + 2 x (p x t) + 2 x (l x t)

= 2 x (20 x 8) + 2 x (20 x 5) + 2 x (8 x 5)

= 320 + 200 + 80

= 600

luas jaring" balok = 600 cm^2

Answer 2

☆Solusi☆

[tex]luas \: jaring - jaring \: balok = luas \: permukaan \: balok[/tex]

[tex] = 2 \times (pl \: + pt \: + lt)[/tex]

[tex] = 2 \times (20cm \times 8cm) + (20cm \times 5cm) + (8cm \times 5cm)[/tex]

[tex] = 2 \times (160cm {}^{2} + 100cm {}^{2} + 40cm {}^{2} )[/tex]

[tex] = 2 \times 300cm {}^{2} [/tex]

[tex] = 600cm {}^{2} [/tex]