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Ao= 40 cm²
ΔL= 0,16 cm²
Δt= 100 °C
Dit:
β=..?
Penye:
β= ΔL/(Ao.Δt)
β= 0,16/(40×100)
β= 0,16/4000
β= 0,00004 /°C
ΔL = 0,16 cm²
Δt = 100 - 0 = 100°C
Ditanya = β..?
Jawab =