Sebanyak X mL larutan KOH 0,2 M dicampur dengan Y mL larutan KOH 0,4 M. jika konsentrasi campuran kedua larutan tersebut 0,3 M maka perbandingan X : Y adalah
Risep
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FoZan
![M_{campuran} = \frac{M_{1}V_{1}+M_{2}V_{2}}{V_{1}+V_{2}} [tex] 0,3 = \frac{0,2X+0,4Y}{X+Y}](https://tex.z-dn.net/?f=M_%7Bcampuran%7D+%3D+%5Cfrac%7BM_%7B1%7DV_%7B1%7D%2BM_%7B2%7DV_%7B2%7D%7D%7BV_%7B1%7D%2BV_%7B2%7D%7D++%5Btex%5D+0%2C3+%3D+%5Cfrac%7B0%2C2X%2B0%2C4Y%7D%7BX%2BY%7D+ "M_{campuran} = \frac{M_{1}V_{1}+M_{2}V_{2}}{V_{1}+V_{2}} [tex] 0,3 = \frac{0,2X+0,4Y}{X+Y}")
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