Question

Sebanyak 90 gram C6H12O6 (glukosa) dilarutkan dalam air sampai volumenya 120 ml. Tentukan M larutan tersebut .

Terimakasih banyak :D

Answer 1

P air = massa jenis x volume
= 1 gr/mL x 120 mL
= 120 gram

m = n x 1000/p
m = 90 gr/180 gr/mol x 1000/120 gr
m = 0,5 mol x 8,333 kg
m = 4,16667 molal

Answer 2

N= G/Mr
n= 90/ (6x12 + 12x1 + 6x16)
n= 90/ (72 + 12 + 96)
n= 90/ 180
n= 0,5 mol

M= n/V
M= 0,5/0,12 L
M= 4,... mol/liter