Question

Sebanyak 90 g CH3COOH (alfa=0,1) dilarutkan dalan 1 liter air. Berapa mol CH3COOH yang mengion? (Ar C = 12, O = 16, H = 1)

Answer 1

Alpha = jumlah mol terionisasi/ jumlah mol mula-mula
diket: alpha = 0,1
CH3COOH = 90 g
mol mula-mula CH3COOH = 90/60 = 1,5 mol

0,1 = jumlah mol terionisasi/1,5 mol
jumlah mol terionisasi= 1,5 . 0,1 = 0,15 mol