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Massa NaCl = 585 gr
Mr = 58,5
Massa Pelarut = 5 Kg
Mol NaCl = Massa/Mr = 585/58,5 = 10 mol
Kemolalan NaCl = Mol/Massa Pelarut = 10/5 = 2 m
NaCl akan terurai menjadi :
NaCl ⇒ Na⁺ + Cl⁻
Sehingga faktor Van Hoff = i = 2
ΔTf = Kf x m x i
ΔTf = 1,86 x 2 x 2
ΔTf = 7,44 ⁰ C
Maka, titik beku larutan :
Tf = 0⁰ C -ΔTf
= 0⁰ C - 7,44⁰ C
= -7,44⁰ C