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M 5 mmol 5 mmol
B 5 mmol 5 mmol 5 mmol 5 mmol
S - - 5 mmol 5 mmol
[OH¯]= vkw/ka . Mgaram
= v1x10¯14 /1x10¯5 . 5/100
= v1x10¯9 . 5x10¯2
= v5 x 10¯11
= 5½ x 10¯5,5
poh = - log (5½ x 10¯5,5)
= 5,5 - ½ log 5
= 5,5 - 0,35
= 5,15
ph= 14- 5,15
= 8,85
m 5 mmol 5 mmol
b 5 mmol 5 mmol 5 mmol
s - - 5 mmol
M CH3COO^- = 5 mmol / 100 mL = 0,05 M
OH- = √10^-14/10^-5 x 0,05 M = 7,07 x 10^-6
pOH = 6 - log 7,07
pH = 8 + log 7,07
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