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Mrnya 98
ΔTb = [massa zat/Mr] x [1000/massa air] x Kb x i
ΔTb = [4,9/98] x [1000/500] x 0,53 x 3
ΔTb = 0,1 x 0,53 x 3
ΔTb = 0,159°C
Maka titik didih larutan Tb = 100° + 0,159° = 100,159°C