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-massa garam = 2,64 gram
-Mr = 132
mol garam = massa = 2,64 = 0,02 mol
Mr 132
Molaritas garam = mol
Volume (dalam liter)
= 0,02
1
= 0,02 M
______________________
[H⁺] = / kw x [konsentrasi garam] ----> seluruhnya diakar ya
√ kb
____________
[H⁺] = /10⁻¹⁴ x 0,02
√10⁻⁵
[H⁺] = 10⁻³ √0,2
pH = -log [H⁺]
pH = -log 10⁻³ x √0,2
pH = 3 - log √0,2
pH = 3 - (-0,35)
pH = 3 + 0,35
pH = 3,35