Mc = (M1V1 + M2V2)/(V1+ V2)
Mc =( 0,2 + 0,01)/(0,2+0,2)
Mc = 0,21/0,4
Mc = 5,25 × 10^-1
pOH = 1-log 5,25
pH = 14-(1-log5,25)
pH = 13 + log 5,25
pH = 13,72
Jadi pH larutan 13,72
====================
Mapel : Kimia
Kelas : XI SMA
Kategori : Asam Basa
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Mc = (M1V1 + M2V2)/(V1+ V2)
Mc =( 0,2 + 0,01)/(0,2+0,2)
Mc = 0,21/0,4
Mc = 5,25 × 10^-1
pOH = 1-log 5,25
pH = 14-(1-log5,25)
pH = 13 + log 5,25
pH = 13,72
Jadi pH larutan 13,72
====================
Mapel : Kimia
Kelas : XI SMA
Kategori : Asam Basa